Using let or var within Swift
I know I know I know before you say anything I understand this statement is probably ridiculous. However, this topic could aid someone or more likely open the floor to discuss concepts in general so without hesitation, we will dive into it.
let and var so what are they and their differences
As you probably already know both let and var are for creating variables within Swift. Now with let it helps create an immutable variable(s) so consider it a constant but var is used for creating a mutable variable(s). Nonetheless, a variable created by either of them holds a reference or a value.
The difference between the two is that when a developer creates a constant with let the value must be assigned before you can use it. While when you declare a variable with var it can be used before or after an assignment or never use it as well as reassigning it on the fly.
Mutate function parms
function parameters are constants by default. Trying to change their value within the function body results in a compile-time error.
func pokedex(for name: String) {
name = "charmander"
}
pokedex(for: "mex")
//Line 2 cannot assign to value is let constant
Test: Build & Compile
struct Pokemon {
var name: String
let weakness: String
}
let trainerAPokemon = Pokemon(name: "Charmander", weakness: "water")
trainerAPokemon .name = "Bulbasaur"
trainerAPokemon .weakness = "fire"
var trainerBPokemon = Pokemon(name: "Pikachu", weakness: "rock")
trainerBPokemon.name = "Squirtle"
trainerBPokemon.weakness = "electricity"
In the example above we are using a struct. Whenever you try to muate them they get copied with mutation applied to them and reassigned back.
Now let’s review everything within the block. The let variable within the struct cant is mutated as it would mean you are mutating the value of an immutable variable. However, our friend the var variable within the struct can be mutated.
- Line 7
- cannot assign to the property trainerAPokemon because it is a let constant
- Line 8 & 12
- cannot assign to the property weakness because it is a let constant
Test: Build & Compile
class Pokedex {
var name: Int
let num: String
init(name: String, num: Int) {
self.name = name
self.num = num
}
}
let trainerA = Pokedex(name: "Lucario", num: 448)
trainerA.name = "Squirtle"
trainerA.num = 7
var trainerB = Pokedex(name: "Bulbasaur", num: 1)
trainerB.name = "Gengar"
trainerB.num = 94
In the example above we are now using a classes. When attempting to mutate them, the object stored elsewhere in memory gets mutated while the reference to it remains the same.
You can modify a class’s members whether or not the variable referencing it is mutable
- Line 13 & 17
- cannot assign to property num because it is a let constant
- Published in blog, iOS, Programming Languages, Swift
Using forEach, forEnumerated, forIn within Swift
Swift provides us with multiple ways to loop through items in a collection, they are:
for pokemon in pokemons {
print(pokemon)
}
pokemons.forEach { (pokemon) in
print("Pokemon", pokemon)
}
for (index, element) in pokemons.enumerated() {
print("Number:", index, "Pokemon:", element)
}
Using for in
many programming languages the for in loo is called for-each. Standard loop statement in other languages uses this format:
for (i = 0; i < n; i++) {
///some fancy collecion to loop thur
}
Please note: Swift 3 no longer supports c-style for-loops
Now when using swift this approach is a little different, the rationale of this for-in syntax is it can be used to loop over ranges, iterators, strings, sequences, and collections with the same syntax.
let pokemons = ["Pikachu", "Charmander", "Squirtle", "Bulbasaur"]
for i in 0...< pokemons.count {
print("Pokemon \(i+1):" pokemons[i])
}
//output:
Pokemon 1: Pikachu
Pokemon 2: Charmander
Pokemon 3: Squirtle
Pokemon 4: Bulbasaur
Within Swift the use of object types like arrays, dictionaries, and sets are known as collection. Any collection can be iterated with a for-in loop. For example with dictionary:
let pokedex = ["Electric":"Pikachu","Water":"Squirtle","Fire":"Charmander","Grass":"Bulbasaur"]
for (type, pokemon) in pokedex {
print("The \(type)'s Pokemon is \(pokemon))
}
//output
The Electric's Pokemon is Pikachu
The Water's Pokemon is Squirtle
The Fire's Pokemon is Charmander
The Grass's Pokemon is Bulbasaur
In addition, Swift also provided two range operators lowerBound...upperBound as a shortcut for expressing a range of values.
Take note: lowebound is greater than upperBound the code will crash
for i in 0...5 {
print(i)
}
//output
0
1
2
3
4
5
for i in 0..<5 {
print(i)
}
//output
0
1
2
3
4
If interested in reversing the range while looping, we can easily achieve that using reversed
for i in (0...5).reversed() {
print(i)
}
//output
5
4
3
2
1
0
Stride
As I referenced before, C-Style for loops are no longer supported within Swift 3, so you’re probably asking how to acquire the ‘increment of the counter’ (i++). We accomplished this by using stride, and this helps us to move from one value to another using any incremental value, we can also specify whether the upperBound is inclusive or exclusive.
for i in stride(from 0, to: 10, by: 2) {
print(i)
}
//output
0
2
4
6
8
Using for each
pokemons.forEach {
print("Pokemon", pokemon)
}
//output
Pokemon Mewtwo
Pokemon Snorlax
Pokemon Eevee
Swift provides a dedicated method forEach for specific, unlike the above forIn this method can’t break the loop partway (at some point). It has to loop over each item in the sequence. It has to loop over each item in the sequence. This helps people reading your code to figure out your intent: that you want to act on all items, and won’t stop in the middle.
Please note:
breakstops execution in a loop immediately and continues directly after the loop.
continueonly exits the current iteration of the loop — it will jump back to the top of the loop and resumes up from there for next iteration
var oddNumbers = [Int]()
for numbers in (0...100) {
guard oddNumbers.count < 15 else {
break
}
guard numbers % 3 == 0 else {
continue
}
oddNumbers.append(numbers)
print(oddNumbers)
}
the same cannot be achieved in forEach with break and continue, so we need something like:
let oddNumbers = (0...100).filter {numbers -> Bool in
return numbers % 3 == 0
}.prefix(10)
print(oddNumbers)
Using for enumerated
This Swift loop iterates to each of the items by also telling the index of it. In case if we need to iterate the elements and need their index also, then forEnumerated is the perfect loop for us.
Nested for loops:
var pokedex = ["001", "002", "003"]
var pokemons = ["Bulbasaur", "Ivysaur", "Venusaur"]
for i in 0..< pokedex.count {
var string = "\(pokedex[i]) is "
for _ in 1...3 {
string += "\(pokemons[i])"
}
print(string)
}
//output
001 is Bulbasaur
002 is Ivysaur
003 is Venusaur
While:
// a while loop performs a set of statements until a condition becomes false
while condition {
//statements
}
var index = 0
while index < pokemons.count {
print(pokemon[index])
index += 1
}
//output
Bulbasaur
Ivysaur
Venusaur
Repeat:
//repeat while loop is similar to do while loops in other languages
repeat {
statements
} while condition
var index = 0
repeat {
print (pokemons[index])
index += 1
} while index < pokemons.count
//output
Bulbasaur
Ivysaur
Venusaur
It is similar to the above while loop but the major difference is that this loop evaluates the condition after running the statements. Either way, both while and repeat are best used in the loops where the numbers of steps are unknown.
- Published in blog, iOS, Programming Languages, Swift
Gradient Views w/Swift
When you want to give the background color to the view, but you want to add more colors and get the gradient effect, you need to add a layer to view,
which we are going to create, in few lines of code.
- Create a CAGradientLayer
var gradientLayer: CAGradientLayer = {
let gradientLayer =CAGradientLayer()
gradientLayer.colors = [#Color1, #Color2] //note: colors you want to use
gradientLayer.startPoint = CGPoint(x:0 y:0)
gradientLayer.endPoint = CGPoint(x:1 y:1)
gradientLayer.frame= CGRect.zero
return gradientLayer
} ()
- Add gradientLayer to the view layer
currentView.layer.addSublayer(gradientLayer)
- Set frame of the gradientLayer
gradientLayer.frame = currentView.bounds
- Published in blog, iOS, Programming Languages, Swift
Working w/Environments in Swift
According to Wikipedia, an Environment Variable is a dynamic-named value that can affect the way running processes will behave on a computer. They are part of the environment in which a process runs. Basically, many developers create 3 environments
- Dev
- Preprod
- Prod
Sometimes we need to separate the base URL and do the initial work which should be done for the following state or condition only.
Create enum for environments
if you need a refresher on enum check out the following article
enum Environment {
case dev
case preprod
case prod
}
Environment Variable
let currentEnvironment = Environment.dev
Execute using a switch statement
switch currentEnvironment {
case .dev:
print("execute only if the environment is development")
case .preprod:
print("execute only if the environment is preprod")
case .prod:
print("execute only if the environment is prod")
default:
break
}
Execute code now
First, we initialize the currentEnvironment variable and using conditions use it. Now we can change the baseUrl in AppDelegate along with other interesting code.
- Published in blog, iOS, Programming Languages, Swift



